-d^2-12d+4=-6d

Solution for -d^2-12d+4=-6d equation:

-d^2-12d+4=-6d

We move all terms to the left:

-d^2-12d+4-(-6d)=0

We add all the numbers together, and all the variables

-1d^2-12d-(-6d)+4=0

We get rid of parentheses

-1d^2-12d+6d+4=0

We add all the numbers together, and all the variables

-1d^2-6d+4=0

a = -1; b = -6; c = +4;
Δ = b2-4ac
Δ = -62-4·(-1)·4
Δ = 52
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{52}=\sqrt{4*13}=\sqrt{4}*\sqrt{13}=2\sqrt{13}$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-2\sqrt{13}}{2*-1}=\frac{6-2\sqrt{13}}{-2}
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+2\sqrt{13}}{2*-1}=\frac{6+2\sqrt{13}}{-2}
$